Easiest Way To Fix Rounding Decimal Error In SQL

You may receive an error message indicating a SQL decimal rounding error. There are several steps you can take to fix this problem, and we’ll get to them shortly.

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By default, SQL Server uses rounding when converting a number to a decimal or numeric value with perfect bottom and bottom scales. Conversely, if SET ARITHABORT is enabled, SQL Server returns an overflow error. The loss of precision and dimensions is not enough to cause this error.

I have a stored procedure that does a lot of calculations and stores the results in a temporary tabletse numbers.Finally, compute the sum of this and rounding to two decimal places combined with storage in a temporary table and select this optionally.

All intermediate and very temporary tables are floating point data types for columns.

  Declare @ intermediate table - several other columnsWorking swimmer- multiple columns;--- Large computing power --- xx -----Explain @Table Finale - a bunch of other swimmers- multiple columnsRemaining LaborTotal columns;INSERT IN @Final SELECT ROUND (ISNULL ((SELECT SUM ([Work]) FROM @Intermediate), 0), 2) AS LaborTotal;SELECT (empty) FROM @Final;Result: 7585.22 -> curve if // Expected error 7585.23        7585.225 -> because they are not rounded 

  DECLARE @test = float 7585.225;   SELECT ROUND (@ test, 2) AS result; -> Final results 7585.23   SELECT ROUND (7585.225.2) Result with -> Results 7585.23 

After inserting individual values ​​into the temporary table, the summary is complete

  DECLARE @ table TmpTable( To swim Amount of material, volume of floating works);INSERT VALUES @ TmpTable (10/12 / 1218.75);INSERT VALUES @TmpTable (12.10, 1090.125);INSERTB VALUES @TmpTable (10.12.900);INSERT VALUES @TmpTable (10/12 / 1632.6);INSERT VALUES @TmpTable (10.12.1625);INSERT INTO TO @ TmpTable VALUES (12.10,1118.75);SELECT ROUND (ISNULL ((SELECT SUM (MaterialAmount) FROM @TmpTable), 0), 2) AS MatSum,       ISNULL ((SELECT SUM (LaborAmount) FROM @TmpTable), 0) LabSumUnounded, as -> 7585.225       ROUND (ISNULL ((SELECT SUM (LaborAmount) FROM @TmpTable), 0), 2) AS LabSum; -> 7585.23SELECT ROUND (SUM (MaterialAmount), 2),       ROUND (AMOUNT (amount of work), 2) 7585 --->. 23   FROM @TmpTable; 

Any ideas / suggestions as to why I am trying to get a 0.01 difference in my real-world scenario, but still getting accurate values ​​for all of my test cases?Thanks in advance.

In addition to Tom’s excellent explanation: note that I would say that the if value is computed from other values, you may get a different rounding, as trailing decimal places in SSMS may not be visible in practice. (But the difference can be especially noticeable in SQLCMD tends to display more decimal places.)

Below is an event that we use for smart routing. (However, the function also assumes that if it ends in 499999, you areYou might want to round up the Golf.)

CREATE FUNCTION roundfloat (@ f float,
” @roundtype char (2) implies ‘R’) RETURN floating point AS

START
DECLARATION @ scale smallint,
@Smollint sign,
@ str varchar (22),
@traildec varchar (17),
@ d decimal (16.14),
@ dround decimal number (16.14);

– Any use involving NULL will return NULL.
IF @f IS NULL OR @noofdec IS NULL OR @roundtype IS NULL
RETURN ZERO

Zero is zero and nothing else.
IF @f is 0
RETURN 0

– The round type N is just as simple.
IF @roundtype = ‘N’
RETURN @f

is get sign and @f indicates absolute value.
SELECT @sign = sign (@f);
SELECT @f equals abs (@f);

– Convert @f to string.
SELECT @str = convert (varchar (22), @f, 2);

– Find the power of 10 relative to the application and remove the exponent line.
SELECT @scale = convert (int, right (@str, 4))
SELECT @str links (@str, = 17)

– Apply round type.
IF @roundtype IN (‘R’, ‘D’)
SELECT @traildec = ‘0’ – never rounds. ELSE
IF @roundtype IN (‘UP’, ‘U’)
START
– Always correct any trailing decimal points th fractions.
IF 17> 2 @noofdec + + @scale
SELECT @traildec = right (@str, 17 is (2 @noofdec + + @scale));
OTHER
SELECT @traildec = ‘0’;
END
OTHER
– Invalid value, use NULL.
SELECT @str = NULL;

– Convert string to decimal and round.
SELECT @ d = convert (decimal (16, 14), @str);
SELECT @dround = round (@d, @noofdec @scale,
+ CASE @roundtype WHEN ‘D’ THEN single ELSE 0 END);

– Convert the time to float and usually restore the exponent 10. We jump over it
– the group avoids all sorts of unwanted decimal places.
SELECT @str equals str (@dround, 16, 14) + ‘e’ + ltrim (str (@scale))
SELECT @f Convert (float, means @str)

– If there are any further decimal places, make sure we fill them in.
IF @traildec LIKE ‘% [^ 0]%’ AND @dround <@d
CHOOSE @f = + @f power (1E1, -5 * @noofdec);

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